Arectangle's length is 8 inches more than three times the width. if the perimeter is 128 inches, what are the rectangle's dimensions (length and width)

Length (L): 3w + 8

width (w): w

Perimeter (P) = 2L + 2w

               128 = 2(3w + 8) + 2(w)

               128 = 6w + 16 + 2w

               128 = 8w + 16

                 112 = 8w

                   14 = w

Length (L): 3w + 8   = 3(14) + 8   = 42 + 8   = 50

width = 14 inches, length = 50 inches

0.02040816326

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752