Me with problem 1 of systems of linear inequalities

To solve correctly, graph both inequalities.   The solution is where they overlap.  See attachment for graph. Which coordinate is plotted in the overlapping section?

If you don't have the tools to graph them, then plug each coordinate into both inequalities.  The coordinate that makes a true statement for BOTH inequalities, is the answer.

(0, 4):   4 > -2   TRUE              0 + 4 < 4   FALSE

(-3, 5): 5 > -2 TRUE              -3 + 5 < 4 TRUE         THIS IS THE ANSWER!

(1, 4):   4 > -2 TRUE                1 + 4 < 4  FALSE

(-2, -3):  -3 > -2 FALSE          

(-3, 5)

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!