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Mathematics, 11.07.2019 14:00 brittsterrr

In the expansion of (1 - \frac{x}{4} ) {}^{n} , the coefficient of x {}^{2} is  \frac{21}{16} . find the value of n.

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In the expansion of [tex](1 - \frac{x}{4} ) {}^{n} [/tex], the coefficient of [tex]x {}^{2} [/tex] i...
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