The number of birds (b) in a park increases when the number of dogs in the park (d) decreases. write the correct equation for this scenario, and solve for the number of birds when there are 10 dogs. dogs birds 40 10 50 8 (1 point)

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form y*x=k or y=k/x

Let

b> the number of birds

d> the number of dogs

in this problem we have

b*d=k

where

k is a constant

when

d=40 dogs  b=10 birds

40*10=400

d=50 dogs  b=8 birds

50*8=400

the value of k=400

the equation is

b=k/d> b=400/d

for d=10 dogs

Find the value of b

b=400/d b=400/10> b=40 birds

therefore

the answer is

40 birds

l.ln.lln.k.nkl

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.