Arocket is scheduled to launch from a command center in 3.75 hours. what time is it now if launch time is 11: 20am. i need to know how to write equation to get answer

t + 3:45 = 11:20 am

Step-by-step explanation:

A rocket is scheduled to launch from a command center in 3.75 hours.

The launch time is 11:20 am.

We need to know the time before 3.75 hours of 11:20 am.

3.75 hours = 3 hours (0.75 × 60) = 45 minutes

Let the current time be 't'

Now the equation will be

t + 3:45 = 11:20 am

t = 11:20 - 3:45

t = 7 : 35 am

Before 3.75 hours of 11:20 am it will be 7:35 am.

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this