One integer is 4 more than 3 times a second integer. their sum is 24. what are the two integers

Let the first integer = x

Let the second integer = y

x = 4 + 3y     (1)

x + y = 24     (2)   Subtract 3y from both sides of (1)

x - 3y = 4      (3)    Subtract (3)  from  (2)

4y = 20          Divide by  4

y = 20/4

y = 5

x + y = 24

x + 5 = 24

x = 24 - 5

x = 19

Answer

x = 19

y = 5

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

answer: the answer is simply nothing.

step-by-step explanation: because there is no ending to this question

gimme brainliest > : 3