The function f(x)=x+3x2−9 is defined everywhere except at x=±3. if possible, define f at x=−3 so that it becomes continuous at x=−3.

The function simplifies to

By defining f(-3) to be 1/(-3-3) = -1/6, we can plug the "hole" at that point, making the function continuous there.

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The attachments show the original function being undefined at x=-3. Defining the function at x=-3 removes the discontinuity.

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

step-by-step explanation:

it will be a cylinder. with a diameter of 8 and 4 single pieces high