Assume that there are 8 rats in the cage: 6 trained and 2 untrained. a rat is removed from the cage and it is noted whether or not it is trained. it is then placed in a different cage. 4 more rats are removed and treated the same way. how many outcomes are possible for this experiment?

First remove:

Probability of removing a trained rat is 6/8

Probability of removing untrained rat is 2/8

Outcome is 6/8 + 2/8 = 1

Second remove:

Probability of picking a trained rat is 5/7

Probability of picking untrained rat is 1/7

Outcome is 6/7

Third remove:

Outcome is 1 (Since you can only remove a trained rat)

Forth remove:

Outcome is 1 (Since you can only remove a trained rat)

Fifth remove:

Outcome is 1 (Since you can only remove a trained rat)

Total outcome = 1 + 6/7 + 1 + 1 + 1 = 34/7 = 4(6/7)

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you