Mathematics, 11.07.2019 06:00 sar1380
Solve the equation check for extraneous solutions. 9 |9 − 8 x| = 2 x + 3 explain how you got it
Answers: 1
![|a|=\left\{\begin{array}{ccc}a&for&a\geq0\\-a&for&a < 0\end{array}\right\\\\|9-8x|=\left\{\begin{array}{ccc}9-8x&for&x\in\left(-\infty,\ \dfrac{9}{8}\right]\\-(9-8x)&for&x\in\left(\dfrac{9}{8},\ \infty\right)\end{array}\right](/tpl/images/0076/0263/f6ff1.png)
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Solve the equation check for extraneous solutions. 9 |9 − 8 x| = 2 x + 3 explain how you got it...
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