5. factor the expression: y2 + 6y – 16 a. (y – 8)(y + 2) b. (y + 8)(y – 2) c. (y + 4)(y + 4) d. (y + 4)(y – 4)

For this case we have the following polynomial:

We must find two numbers that comply with:

1) The algebraic sum of the numbers is equal to 6.

2) The multiplication of the numbers is equal to -16.

Therefore, factoring the polynomial we have:

The factored expression is:

b. (y + 8) (y - 2)

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."