Abasketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. she misses the first shot 40% of the time. when she misses the first shot, she misses the second shot 5% of the time. what is the probability of missing both free-throw shots?

The answer is 2%

Here is how I got it:

40/100 x 5/100 or 0.04 x 0.05

= 0.02

= 2%

Hope this helps

-AaronWiseIsBae

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.