Select the equation of the line in which the x-intercept is -5, and the y-intercept is 10. y-10= 1/2x y-2= -2(x+4) y-4=2(x+3) y+3=2(x-4)

The 2 points given are (-5,0) and (0,10) so

the slope = (10-0) / (0-(-5))  = 10/5

= 2

using the point-slope form of equation of a straight line and the point (0,10):-

y - 10 = 2(x - 0)

y = 2x + 10

This  is the same equation as option C , y - 4 = 2(x + 3)

Its C