Aright cone has a height of 55 and a slant height of 73. what is the radius of the circular base? enter your answer as a number, like this: 42

To find the radius of the circular bad, use the Pythagorean thereom.

A^2 + B^2 = C^2

Substitute A^2 with the height, 55, and C^2 with the slant height, 73.

55^2 + B^2 = 73^2

Then simplify

3025 + B^2 = 5329

Subtract 3025 from both sides

B^2 = 2304

Find the square root of both sides

B = 48

The radius of the base of the cone is 48.

If you have any frther questions feel free to ask.

Hope this helps.

1 is c

2 is a

3 is a

step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1