Mathematics, 10.07.2019 22:30 lizzzyyy60

Find x- and y-intercepts. write ordered pairs representing the points where the line crosses the axes. 1. y=5x−10 2. y=2x−3 3. x+4y=12 4. x−y=4 5. y=−2x 6. y−4x=0 7. 0.3x−0.4y=0.7 8. y= 2/3 x− 1/3

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Answer from: lolz55678

1. y=5x-10

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

y=5x-10

0=5x-10

10=5x

∴ x=2

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

y=5x-10

y=5(0)-10

y=0-10 =

∴ y=-10.

The ordered pairs representing the points where the line y=5x-10 crosses the axes are, (2,0) and (0, -10) .

2. y=2x-3

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

y=2x-3

0=2x-3

3=2x

∴ $x=\frac{3}{2}$

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

y=2x-3

y=2(0)-3

y=0-3 =

∴ y=-3.

The ordered pairs representing the points where the line y=2x-3 crosses the axes are, $(\frac{3}{2} ,0)$ and (0, -3) .

3. x+4y=12

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

x+4y=12

$x+4\cdot (0)=12$

x+0=12

∴ x=12

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

x+4y=12

0+4y=12

4y=12

∴ y=3.

The ordered pairs representing the points where the line x+4y=12 crosses the axes are, (12, 0) and (0, 3) .

4. x-y=4

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

x-y=4

x-0=4

∴ x=4

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

x-y=4

0-y=4

y=-4

∴ y=-4.

The ordered pairs representing the points where the line x-y=4 crosses the axes are, (4, 0) and (0, -4) .

5. y=-2x

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

y=-2x

0=-2x

∴ x=0

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

$y=-2\cdot(0)$

y=0

∴ y=0.

The ordered pairs representing the points where the line y=-2x crosses the axes is, (0, 0)

6. y-4x=0

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

y-4x=0

0-4x=0

-4x=0

∴ x=0

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

y-4x=0

$y-4\cdot (0)=0$

y-0=0

∴ y=0.

The ordered pairs representing the points where the line y-4x=0 crosses the axes is, (0,0)

7. 0.3x-0.4y=0.7

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

$0.3x-0.4\cdot (0)=0.7$

0.3x-0=0.7

$x=\frac{0.7}{0.3}$

∴ $x=\frac{7}{3}$

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

$0.3\cdot(0)-0.4y=0.7$

0-0.4y=0.7

-0.4y=0.7

$y=-\frac{0.7}{0.4}$

∴ $y=-\frac{7}{4}$

The ordered pairs representing the points where the line 0.3x-0.4y=0.7 crosses the axes are, $(\frac{7}{3} , 0)$ and $(0, -\frac{7}{4} )$ .

8. $y=\frac{2}{3}x-\frac{1}{3}$

To find the x-intercept of the given linear equation , plug in y=0 and solve for x.

$0=\frac{2}{3}x-\frac{1}{3}$

$\frac{2}{3}x=\frac{1}{3}$

$x=\frac{1}{3}\cdot \frac{3}{2}$

∴ $x=\frac{1}{2}$

Now, to find the y-intercept for the given linear equation we plug in x=0 and solve for y.

$y=\frac{2}{3}\cdot (0)-\frac{1}{3}$

$y=0-\frac{1}{3}$

∴ $y=-\frac{1}{3}$

The ordered pairs representing the points where the line $y=\frac{2}{3}x-\frac{1}{3}$ crosses the axes are, $(\frac{1}{2}, 0)$ and $(0, -\frac{1}{3} )$

Answer from: Quest

2x^2+5x+17

your welcome. : )

Answer from: Quest

The answer is d, none of above hope i

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