For number 28 you need to use point-slope form, which is y-y1=m(x-x1), through the points (4, 2) and (-2, 5) for number 29 you need to use point-slope form, once again it’s y-y1=m(x-x1), through the point (-2, -1) and is perpendicular to y= -2 for questions 30 through 35 the radicals need to be simplified. not in decimal form, though. me, it would be greatly appreciated. you so much!

28) Slope is (5-2)/(-2-4) = 3/-6 = -1/2 so a possible point-slope form is

y - 2 = -1/2(x-4)

29) y = -2 is a horizontal line. If you are wanting a line perp. to a horizontal line, you get a vertical line of the form x = a. Since it passes through (-2,-1), the point slope form is just x = -2 (there's no real point slope form because there is no y. vertical line does not care about y; all the y-values are on the vertical line)

30) Since 25*3 = 75, √(75) = √(25*3)=√25 * √3 = 5√3

31) √128 = √(64 * 2) = 8√2

32) √144 = 12 because 12*12 = 144

33) 4√(54) = 4√(9*6) = 12√6

34) 2√(32) = 2√(16*2) = 8√2

35) -6√175 = -6√(25*7) = -30√7

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation: