How many liters of a 2% hydrochloric acid(hci) solution and an 11% hci solution should karen mix to obtain 3 l of the 8% hci solution needed in the chemistry lab?

Let x liters of a 2 % HCL is mixed with (3-x) liters of 11 % HCL solution to obtain 3 liters of 8% HCL solution. So the equation will be

Distributing 0.11 on 3-x, we will get

Combining like terms

Dividing both sides by -0.09

So 1 liter of 2 % HCL solution is mixed with 2 liters of 11% HCl solution to get 3 liters of 8% HCL solution .

idk

step-by-step explanation:

step-by-step explanation:

where is the questions