Find a number that is 68 greater than three times its opposite

These are fun! Let's make a math sentence.

Our number is x.

We are told that x is equal to 68 more than 3 (-x)

x=3(-x) + 68 is our final equation

Now solve.

x = -3x + 68 Subtract -3x from both sides to move the variables to the left.

x -(-3x) = 68 Change the two minuses to a plus

x+3x = 68 Add the variables

4x = 68 Divide both sides by 4 to leave only x.

x = 17

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers