Hi i need halp on mi homewurk. heer is mai problim. plees solv and explayn. x-32=y+13^2 thakns!

So, we have a problem here. Our equation is x-32=y+13^2

First, we want to use exponents on the right side. 13^2=169

Now we have a simplified equation of: x-32=y+169

Now, add 32 to both sides: x=y+201

Since there is no given value for y, we have our answer.

x=y+201

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

answer: what in the world is this

step-by-step explanation: