Agent hunt transferred classified files from the cia mainframe onto his flash drive. the drive had some files on it before the transfer, and the transfer happened at a rate of 4.4, megabytes per second. after 32 seconds, there were 384 megabytes on the drive. the drive had a maximum capacity of 1000 megabytes. how full was the drive when the transfer began? megabytes how long from the time that agent hunt started the transfer did it take the drive to be completely full? seconds

Part a.

The drive had some files before the transfer. We don't know the number of megabytes already on the drive, so we call it x. x is the number of megabytes on the flash drive before Agent Hunt started the transfer.

He transferred files at a rate of 4.4 megabytes per second for 32 seconds. That gives a total of 4.4 Mb/sec * 32 sec = 140.8 transferred megabytes.

He ended up with 384 megabytes.

x + 140.8 = 384

Now we can solve for x, the number of megabytes originally on the flash drive.

x = 384 - 140.8

x = 243.2

The flash drive has 243.2 megabytes when the transfer began.

Part a. 243.2 megabytes

Part b.

The total capacity if the flash drive is 1000 megabytes. He already had 243.2 megabytes on it before this transfer. 1000 Mb - 243.2 Mb = 756.8 megabytes

The flash drive has capacity for an additional 756.8 megabytes when he started the transfer. The rate of transfer is 4.4 megabytes/second.

756.8/4.4 = 172

Part b. 172 seconds

only 10/60 isn't equivalent

hope this : )

∠cbe and ∠deb are same-side interior angles.

i took the test