The sum of three consecutive integers is negative 114 find the integers

So let's call the smallest of the three integers a.

Therefore,

(a) + (a+1) + (a+2) = -114.

Combining the like terms, we get:

3a + 3 = -114

Subtracting 3 on both sides to leave the variables on one side, we get:

3a =  -117

Finally, dividing both sides by 3 to isolate the variable, we have:

a = -13.

Therefore, the smallest of the integers is -13.

Since our original equation was:

(a) + (a+1) + (a+2) = -114,

we plug -13 for each time we see a.

Therefore, the three integers are:

-13, -12, and -11.

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!