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![f(1)=3\\\\f(n)=[f(n-1)]\\\\f(2)=[f(2-1)]=[f(1)]=[3]=3\\\\f(3)=[f(3-1)]=[f(2)]=[3]=3\\\\f(4)=[f(4-1)]=[f(3)]=[3]=3\\\\f(5)=[f(5-1)]=[f(4)]=[3]=3](/tpl/images/0073/9621/0115b.png)
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Write the first 4 terms for f (1) = 3, f (n) = [f(n-1)]...
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