In planning her retirement, liza deposits some money at 2.5% interest, with twice as much deposited at 4.5%. find the amount deposited at each rate if the total annual interest income is $1150.

Let us assume $x is deposit at 2.5% interest.

At the rate 4.5% deposited amount is twice of the amount deposited at 2.5%.

Therefore, at the rate 4.5% deposited amount = $2x.

Total interest earned by both different deposited amount at the rate 2.5% and at the rate 4.5% = $1150.

We can setup an eqation now,

Interest earned on $x at 2.5% + interest earned on $2 at 4.5% = $1150.

2.5% of x + 4.5% of 2x = 1150

Percentage could be written in decimals by dividing by 100.

Therefore, 2.5% = 2.5 /100= 0.025 and 4.5% = 4.5/100 = 0.045.

We could rewrite above equation as,

0.025*x + 0.045 * 2x = 1150

0.025x + 0.09x =1150

Adding 0.025x + 0.09x, we get 0.115x.

So, 0.115x=1150.

Dividing both sides by 0.115.

0.115x/0.115=1150/0.115.

x= $1000.

2x= 2* 1000= $2000

Therefore,

$1000 deposited at 2.5% and $2000 deposited at 4.5%.

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation: