One coin is randomly selected from a jar containing 70 nickels, 100 dimes, 80 quarters and 50 one-dollar coins. what is the probability of selecting a coin with a value greater than $0.10?

Add all the coins together for the total coins:

70 + 100 + 80 + 50 = 300 total coins.

The only coins greater than 0.10 are the quarters and one-dollar coins.

Total of those two coins: 80 + 50 = 130 coins.

Probability of picking one of those = 130 / 300, which reduces to 13/30

step-by-step explanation:

how many centimeters did the level of the salsa go down by?

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)