Graph the image of the given triangle under a dilation with a scale factor of 1/3 and center of dilation (0, 0) . to graph the triangle, select the "polygon" tool and draw the triangle by plotting each vertex in order until it lands back on the first vertex. do not retrace any sides. you may use the "move" tool to move your image if you needed.

We are given : A scale factor of 1/3 and center of dilation (0, 0).

For the given image, the coordinates of the vertices of the triangle are

(0,9), (0,0) and (-6,0).

We can apply formula for finding new coordinates:

Scale factor * [Vertex coordinates of the given image - Coordinate of Center of dilation] +Coordinate of Center of dilation.

Applying same formula to each coordinates we are given.

(0,9) --> 1/3 [ (0,9) - (0,0) ] + (0,0) ]  = 1/3 [ (0,9)] +(0,0) = (0,3).

(0,0) --> 1/3 [ (0,0) - (0,0) ] + (0,0) ]  = 1/3 [ (0,0] +(0,0) = (0,0).

(0,9) --> 1/3 [ (-6,0) - (0,0) ] + (0,0) ]  = 1/3 [ (-6,0)] +(0,0) = (-2,0).

Now, we can plot those resulting coordinates on the graph and form a triangle.

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.