Answers: 1
![\bf \boxed{3}~\hspace{7em}\sqrt{7x-2}=\sqrt{7-6x}\implies \stackrel{\textit{squaring both sides}}{(\sqrt{7x-2})^2=(\sqrt{7-6x})^2} \\\\\\ 7x-2=7-6x\implies 13x=9\implies x=\cfrac{9}{13} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{4}~\hspace{7em}6\sqrt{x-2}=\sqrt{x+8}\implies (6\sqrt{x-2})^2=(\sqrt{x+8})^2 \\\\\\ 6^2(\sqrt{x-2})^2=x+8\implies 36(x-2)=x+8\implies 36x-72=x+8 \\\\\\ 35x=80\implies x=\cfrac{80}{35}\implies x=\cfrac{16}{7}](/tpl/images/0072/8654/e7695.png)
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