An object is launched from a platform. it’s height (in meters), x seconds after the launch, is modeled by h(x)=-5(x+1)(x-9) how many seconds after the launch will the object hit the ground

9 seconds

Explanation:

The height will be zero when the object hits the ground. So we need to find the x value(s) that make h(x) = 0 true.

h(x) = 0

-5(x+1)(x-9) = 0

x+1=0 or x-9=0 <--- use zero product property

x=-1 or x=9

The value x represents the time in seconds. Having x = -1 seconds makes no sense, so we ignore that value entirely. The only practical solution is x = 9.

After 9 seconds, the object will have a height of 0. This means the object will hit the ground at the 9 second mark.

answer: b.48 for

step-by-step explanation:

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.