Consider the functions f(x)=3x^2 - 5 and g(x)= √x -5 +2 how can i find f(5) g(5) f(4) g(4) describe the domain of f(x) describe the domain of g(x) why is the domain of one of these functions more restructive than the other?

F(5):

G(5):

F(4):

G(4):

Hope it helped,

BioTeacher101

f(x) = 3x² - 5      

f(5) = 3(5)² - 5   →   f(5) = 3(25) - 5   →   f(5) = 75 - 5   →   f(5) = 70

f(4) = 3(4)² - 5   →   f(4) = 3(16) - 5   →   f(4) = 48 - 5   →   f(5) = 43

DOMAIN of f(x): All real numbers (because there are no restrictions on "x")

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g(x) = + 2

g(5) = + 2  →  g(5) =   + 2   →   g(5) = 2

g(4) = + 2   →  g(4) =   + 2   →   g(4) = no real solutions

DOMAIN of g(x): x ≥ 5    (because you cannot take the square root of a negative number)

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v