Solve 4(x - 3) - 2(x - 1) > 0.a.{x | x > 2}b.{x | x > 5}c.{x | x > 7}d.{x | x > 14}

Remark

Remove the brackets. Then solve as a normal inequality.

Solution

4(x - 3) - 2(x - 1) > 0

4x - 12 - 2x + 2 > 0    Combine like terms on the left

4x - 2x - 12 + 2 > 0

2x - 10 > 0                 Add 10 to both sides

2x > 10                       Divide by 2

x > 10/2

x > 5

B

Discussion

C and D are both true but these questions always assume that you are going to pick the lowest value that will allow the inequality  to be true. x> 7 and x>14 will be included in x>5

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

this is false ^.^ lol