If two people are randomly chosen from a group of eight women and six men, what is the probability that (a) both are women; (b) both are men; (c) one is a man and the other a woman?

a) Choice 1: 8 women out of 14 total, Choice 2: 7 women out of 13 remaining

x = =  ≈ 30.8%

b) Choice 1: 6 men out of 14 total, Choice 2: 5 men out of 13 remaining

x = =  ≈ 16.5%

c) Choice 1: 8 women out of 14 total, Choice 2: 6 men out of 13 remaining

x = =  ≈ 26.4%

answer: (1,3) and (-2,0) i think.

your question is incomplete, write all the numbers in the sequence that it tells you.  

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