What is sec(arctan x/2) show steals .

sec(α)² = 1+tan(α)²

sec(α) = √(1+tan(α)²)

You have α = arctan(x/2), so tan(α) = x/2.

sec(α) = √(1+(x/2)²)

sec(arctan(x/2)) = (1/2)√(x²+4)

Using SOH CAH TOA, you can draw a right triangle with adjacent side 2 and opposite side x. The angle of interest will then have a tangent equal to O/A = x/2. The secant is the reciprocal of the cosine, so is H/A. You can find H using the Pythagorean theorem. It is √(2²+x²), so you have

... secant(arctan(x/2)) = (√(4+x²))/2 . . . . as above

step-by-step explanation:

dong do iy iys a scram

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13