The length of a rectangle is 88 inches longer than the width. if the perimeter of the rectangle is 7272 inches, find the measures of the length and width.

The perimeter (IP) of a rectangle is

P = 2(length + width)

let width = w then length = w + 88

P = 2(w+w+88) = 2(2w+88) = 4w+176

Thus P = 4w+176 = 7272

hence 4w = 7272 - 176 = 7096

so w = 7096/4 = 1774

width = 1774 inches and length = w+88 = 1774+88 = 1862 inches

don't know sorry bru

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet