Find two consecutive odd integers such that their product is 119 more than 7 times their sum.

Answer - (19 and 21) or (-7 and -5)

Solution -

let the first odd number is x,then its next odd number will be x+2.

So sum of these numbers = x + (x+2) and product of these numbers x × (x+2)

from the question it can be concluded that

x(x+2) = 7(x+x+2) + 119

⇒ x²+ 2x = 7(2x+2) + 119

⇒ x² + 2x = 14x + 133

⇒ x² - 12x - 133 = 0

⇒ x² - 19x + 7x - 133 = 0

⇒ x(x-19) + 7(x-19) = 0

⇒ (x-19)(x+7)=0

⇒ x = 19, -7

so here the value of x is either 19 or -7

if the first odd number is 19 ,then the next odd number is 21 and if the first number is -7, then the next number should be -5.

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step-by-step explanation: