What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m. show your work. you!

An isosceles trapezoid has 2 parallel sides and equal non-parallel legs. The height of the isosceles trapezoid is 2.65 m

Because the trapezoid is isosceles, the 2 legs of the trapezoid will be equal.

I have added an attachment that represents the given trapezoid.

From the attachment, we have:

--- length of the leg

---- base of the triangle formed by the leg of the trapezoid

The height (h) is calculated using the Pythagoras theorem as follows:

So, we have:

Collect like terms

Take square roots of both sides

Hence, the height of the trapezoid is 2.65 m

Read more about isosceles trapezoid at:

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Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,

Consider right triangle ABE, by the Pythagorean theorem

d

step-by-step explanation:

d

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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