In the right △abc with m∠c=90°, m∠b=75°, and ab=12 cm. find the area of △abc.

Given that ABC is a right angle triangle with m∠C=90°,  m∠B=75° and AB=12cm.

Area of triangle =

                          =

So we need to find BC,AC now.

To find them let us take sinB and cosB.

SinB =

BC = 12* cos B = 12* cos 75

So, area =

             = 72*sin(75)*cos(75)

             = 36*(2sin(75)cos(75))

             = 36*sin(150) =  18

Hence area of triangle is 18

50- 250 is correct i did that one too

step-by-step explanation:

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step-by-step explanation:

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