What is the equation of the line that is perpendicular y=1/5x+4 and that passes through (5,–4)?

The equation of the line that passes through (5, -4)

and is perpendicular to line y = 1/5x + 4

is y= -5x + 21

The slope that is perpendicular to the slope 1/5x is -5x.

To find a perpendicular slope, you take the negative reciprocal.

The negative reciprocal of 1/5x is -5/1x, or -5x

However, y = -5x + 4 does NOT pass through (5, -4)

Looking at the line on a graph, we can find that if the y-intercept is 21, it  DOES pass through (5, -4)

5x+10 is the correct one

hope this

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)