Find a normal vector n to the plane z−5(x−2)=2(8−y)

A normal vector is the set of coefficients of x, y, and z when the equation is written in standard (or general) form.

Subtracting the left side, we have

... 2(8 -y) -z +5(x -2) = 0

... 16 -2y -z +5x -10 = 0

... 5x -2y -z +6 = 0 . . . . . general form

A normal vector is (5, -2, -1).

false

step-by-step explanation:

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )