Calculate the cross product assuming that u × w = 0, 1, 3 . (2u + 3w) × w

Answer- (2u + 3w) × w =  < 0, 2, 6 >

Solution -

Given in the problem

(u × w) = < 0, 1, 3 >

Then,

(2u + 3w) × w = (2u × w) + (3w × w)

(2u × w) = 2(u × w) = < 0×2, 1×2, 3×2 > = < 0, 2, 6 >  ( ∵ Multiplying it by 3 with all components)

(3w × w) = 3(w × w) = 0                                               ( ∵ The cross product of any vector with itself is 0)

∴ (2u + 3w) × w =  < 0, 2, 6 >

what do you need me to answer?

step-by-step explanation:

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a