Assume that an int variable x that has already been declared, and initialized to a non-negative value. write an expression whose value is the last (rightmost) digit of x.

We know that an int variable, x, has been declared

It has been assigned a non-negative value

We need to write an expression that extracts the rightmost digit of x

The logic for doing so would be to divide the number by 10, and checking the remainder. The remainder will always yield the rightmost digit. In case the number is a multiple of 10 then the remainder would be 0 (which would be the rightmost digit of the number)

So we can do so by:

int y = x % 10;

% is the modulo function, which returns the remainder after carrying out division

we have declared y to be int, as % will always return int values.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

20%

step-by-step explanation: