During the first 50 minutes of flight, the concorde climbs from ground level to an altitude of about 52,000 ft. what is the concordes rate of change in altitude during this time? round your answer to the nearest hundred

Let

x--------> the time in minutes

y-------> an altitude in feet

we know that

For x=0 min  y=0 ft

For x=50 min y=52,000 ft

so

the rate of change is equal to calculate the slope of the linear equation

Round to the nearest hundred-------->

therefore

the answer is

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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