What is the distance between k(2,3),f(4,4)

You would solve this as if it were a triangle. The distance between these 2 points is 2 in the x-value and 1 in the y-value. You use the Pythagorean theorem to find the rest, so 2^2+1^2=c^2 then becomes

4+1=c^2 which is then 5=c^2

c=about 2.236 units and that is the distance between the 2 points.

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}