Mathematics, 09.07.2019 10:00 sama3638
What is the equation of the quadratic graph with a focus of (3,4) and a drirectrix of y =8
Answers: 1
![\bf \textit{parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=3\\ k=6\\ p=-2 \end{cases}\implies 4(-2)(y-6)=(x-3)^2\implies -8(y-6)=(x-3)^2 \\\\\\ y-6=\cfrac{(x-3)^2}{-8}\implies \blacktriangleright y=-\cfrac{1}{8}(x-3)^2+6 \blacktriangleleft](/tpl/images/0069/0258/7de42.png)
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What is the equation of the quadratic graph with a focus of (3,4) and a drirectrix of y =8...
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