Astudent theater charges $9.50 per ticket. a. the theater has already sold 70 tickets. identify an inequality that represents how many more tickets xx the theater needs to sell to earn at least $1000. 70+9.50x≥100070+9.50x≥1000 (9.50)(70)+x≥1000(9.50)(70)+x≥1000 9.50(70+x)≥10009.50(70+x)≥1000 1000≥(9.50)(70)+9.50x1000≥(9.50)(70 )+9.50x question 2 solve the inequality.

Answer-

The inequality equation for the given problem is "9.50(70+x) ≥ 1000"

And the theater need to sell 36 more tickets in order to get at least $1000.

Solution-

Let's assume x is the number of more tickets to sell in order to get at least  $1000  and the price of one ticket is $9.50.

No. of tickets already sold by the theater = 70

So total earnings till now = $(70 × 9.50)

Total earnings by selling x tickets = $(x × 9.50)

∴ Hence, the inequality equation is,

 ( ∵ since tickets can only be sold as whole)

∴ So, the theater need to sell 36 more tickets in order to get at least $1000.

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.