Mathematics, 09.07.2019 05:30 justiceharris8
Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. since this is a polynomial of degree 4 and he only sees two zeros, he determines that the fundamental theorem of algebra does not apply to this equation. is jamison correct? why or why not? a) no, the root 3 has multiplicity of 3. b) no, there are two imaginary solutions. c) no, the root −2 has multiplicity of 3. d) yes, the fundamental theorem of algebra does not apply to this equation.
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Jamison graphs the function ƒ(x) = x4 − x3 − 19x2 − x − 20 and sees two zeros: −4 and 5. since this...
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