An object moves from the position +16 m to the position +47 m in 12 s. what is its total displacement? what is its average velocity?

Given that an object moves from the position +16 m to the position +47 m in 12 s. Now we need to find about what is its total displacement and what is its average velocity.

We know that displacement is the object's overall change in position.

So total displacement is given by:

Displacement = (+47) - (+16) = +31

Now velocity is given by ratio of displacement and time so final answer for velocity will be :

Which is approx 2.6 m/s.

The displacement is the distance that exists between the end position and initial position of an object, and is independent of the trajectory.

Then, for this problem, the object started the movement from a point at 16 meters to a point at 47 meters.

Then the displacement of the object was:

Then, the average speed of the object is the distance that displaced between the time it did (12 seconds).

So:

Where:

d is the displacement

v is the average speed

v = 2.58 m / s

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!