Given: abcd ∥gram, bk ⊥ ad , ab ⊥ bd ab=6, ak=3 find: m∠a, bk, a

Given: ABCD ∥gram,

BK ⊥ AD , AB ⊥ BD

AB=6, AK=3

Find: m∠A, BK

To proof

  as given BK ⊥ AD

thus ΔABK is a right triangle.

thus by using the pythagoras theorem

we have

AB² = BK² + AK²

BK²  = AB ²- AK²

     = 6² - 3²

     = 36 - 9

     = 27

Hence

BK = unit

Now find the value  m∠A

by using the trignometric function

FORMULA

cosA =

cosA =

       =

m∠A = 60°

hence proved

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

tried on you are knowing that we can't leave the picture in the graph ok no problem now you need to send it in the question group