Can someone me with this geometry problem? angle proof given: 1. ray bf bisects < abc, m< abd = m< cbe prove: m< dbf = m< ebf

1. ray BF bisects ∠ABC                   1. given

   m∠ABD = m∠CBE              

2. ∠ABF ≅ ∠ CBF                            2. angle bisector theorem

3. m∠ABF = m∠CBF                        3. definition of congruency

4. m∠ABF = m∠ABD + m∠DBF       4. angle addition postulate

  m∠CBF = m∠CBE + m∠EBF

5. m∠ABF = m∠CBE + m∠DBF      5. substitution (s1: m∠ABD = m∠CBE)

6. m∠CBF = m∠CBE + m∠DBF       6. substitution (s3: ∠ABF = ∠ CBF)

7. m∠CBE + m∠DBF = m∠CBE + m∠EBF   7. transitive property

8. m∠DBF =  m∠EBF                        8. subtraction property

1.5%

step-by-step explanation:

its d. the first coordintaes are 10,32

step-by-step explanation: