The sum of 3 consecutive odd integers is 18 less than five times the middle number. find the three integers

n, n + 2, n + 4 - three consecutive odd ntegers

n + (n + 2) + (n + 4) = 5(n + 2) - 18     |use distributive property

n + n + 2 + n + 4 = (5)(n) + (5)(2) - 18

3n + 6 = 5n + 10 - 18

3n + 6 = 5n - 8     |subtract 6 from both sides

3n = 5n - 14     |subtract 5n from both sides

-2n = -14    |divide both sides by (-2)

n = 7

n + 2 = 7 + 2 = 9

n + 4 = 7 + 4 = 11

7, 9, 11.

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step-by-step explanation:

- (2, -7)

- lines r and s and lines t and u must be parallel