Solve the following system of equations by using the substitution method. y= 6x - 11 -2x - 3y = -7 - (1,2) - (2,1) - (-3,1) - (2,4)

Use the first equation   (y= 6x - 11)   to simplify the second equation (reduce the number of variables there from 2 to 1):

-2x - 3(6x - 11) = -7

-2x - 18x + 33 = -7.  Combining like terms, -20x = -40, or x = 2.

If x = 2, use the first equation to determine y:  y = 6(2) - 11 = 1

The solution is (2,1).

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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