Which statement best compares the value of the 4 in each of these numbers? a: 16.942 b: 9.214 a) (40 < 400) the value of the 4 in a is 40, and the value of the 4 in b is 400. b) (.4 < .004) the value of the 4 in a is .4, and the value of the 4 in b is .004. c) (.04 > .004) the value of the 4 in a is .04, and the value of the 4 in b is .004. d) (.004 > .04) the value of the 4 in a is .004, and the value of the 4 in b is .04.

First, let us write the place values of 4 in A and B.

In A, the number is 16.942 and the place value of 4 is 0.04.

In B, the number is 9.214 and the place value of 4 is 0.004.

It is clear that 0.04 > 0.004.

Hence, statement C best compares the value of 4 in each number.

you have 6 cupcakes

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right