Apebble fall into a pond from the surface sealevel it descends at a rate of 2feet per second where is the pebble in relation to the surface of the pond after 5 second

Pebble falls into the pond from the surface and it descends at a rate of 2 feet per second.

So basically, the pebble is descending or falling down at 2 feet per second which means after every 1 second, it goes 2 feet down.

The equation to represent the depth of the pebble with time is given by:

Where, 'd' is the depth after certain time and 't' is the time in seconds.

Now, we need to find the depth of the pebble after 5 seconds.

Plugging the value , we get:

So, after 5 seconds the pebble will be at the depth of 10 feet.

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

28

step-by-step explanation:

because that's the answer